1 00:00:26,826 --> 00:00:26,881 “ 2 00:00:26,882 --> 00:00:26,937 “L 3 00:00:26,938 --> 00:00:26,993 “Le 4 00:00:26,994 --> 00:00:27,049 “Lev 5 00:00:27,050 --> 00:00:27,105 “Leve 6 00:00:27,106 --> 00:00:27,160 “Level 7 00:00:27,161 --> 00:00:27,216 “Level 8 00:00:27,217 --> 00:00:27,272 “Level a 9 00:00:27,273 --> 00:00:27,328 “Level as 10 00:00:27,329 --> 00:00:27,384 “Level ass 11 00:00:27,385 --> 00:00:27,440 “Level asse 12 00:00:27,441 --> 00:00:27,496 “Level asses 13 00:00:27,497 --> 00:00:27,552 “Level assess 14 00:00:27,553 --> 00:00:27,608 “Level assessm 15 00:00:27,609 --> 00:00:27,664 “Level assessme 16 00:00:27,665 --> 00:00:27,720 “Level assessmen 17 00:00:27,721 --> 00:00:27,775 “Level assessment 18 00:00:27,776 --> 00:00:27,831 “Level assessment” 19 00:00:27,832 --> 00:00:27,887 “Level assessment” 20 00:00:27,888 --> 00:00:27,943 “Level assessment” t 21 00:00:27,944 --> 00:00:27,999 “Level assessment” ta 22 00:00:28,000 --> 00:00:28,055 “Level assessment” tab 23 00:00:28,056 --> 00:00:28,456 “Level assessment” tab 24 00:00:28,481 --> 00:00:34,647 One tool for evaluating the binary inputs that should be preserved during the test is “level assessment”. 25 00:00:34,672 --> 00:00:40,543 In “level assessment” tab, the binary situation of the device inputs can be assessed at the start of a “state”. 26 00:00:40,568 --> 00:00:43,014 An example is provided for this process. 27 00:00:43,038 --> 00:00:46,570 First three “states” are created in the window “table view”. 28 00:00:46,595 --> 00:00:51,469 then, the range of voltage signals are inserted as “30” v in “state1”. 29 00:00:51,493 --> 00:00:54,825 The value of “4” s is inserted in the “trigger”. 30 00:00:54,849 --> 00:01:00,545 Then, the value of “10” v is inserted in “state2” and its time is set as “3” second. 31 00:01:00,569 --> 00:01:06,042 The value of “30” v is inserted in “state3” and its time is set as “4” seconds. 32 00:01:06,066 --> 00:01:10,696 In the following, by clicking “hardware configuration” in the tab “analog out”, 33 00:01:10,728 --> 00:01:13,061 current signals become deactivated. 34 00:01:13,085 --> 00:01:19,784 The binary inputs 3 and 4 can be activated in the tab “binary/analog input” in “binary-input target”; then 35 00:01:19,808 --> 00:01:21,238 they are assigned a name. 36 00:01:21,262 --> 00:01:24,424 Here, the type of binary inputs is set as “dry”. 37 00:01:24,448 --> 00:01:29,287 Then in the window “measurement view”, click on tab “level assessment”. 38 00:01:29,311 --> 00:01:35,319 In this tab by clicking “state name”, the names of the existing “states” are inserted in “table view”. 39 00:01:35,344 --> 00:01:40,750 This name is uneditable. Note that in this tab, you cannot add a line manually. 40 00:01:40,824 --> 00:01:49,039 In the“level assessment” tab , the right click tool is deactivated, and for every “state” in the window “table view”, a line has been created in this tab. 41 00:01:49,087 --> 00:01:55,114 So, the number of assessments in this section depends on the number of “states” existing in the “table view” window. 42 00:01:55,138 --> 00:01:58,708 The result of assessment is presented in the “assessment” column. 43 00:01:58,732 --> 00:02:06,285 The value of time tolerance for assessment of the zero or one level of the binary input is entered into the column “tolerance”. 44 00:02:06,309 --> 00:02:17,377 It can be simply stated that assessment of the level of every signal at the right and left sides of the starting point of every state depends on the value of time tolerance specified in this part. 45 00:02:17,401 --> 00:02:23,253 Suppose that the value of 30 ms is inserted as the tolerance of a binary input, 46 00:02:23,277 --> 00:02:28,793 the figure presents the schematic level assessment of the signal of this binary input. 47 00:02:29,261 --> 00:02:40,166 As it is obvious, level assessment at the two sides of state2 is done by a time tolerance of 30 ms in order to check the condition specified for this assessment; 48 00:02:40,190 --> 00:02:43,901 for example the level of the binary input should be equal to 1. 49 00:02:43,958 --> 00:02:52,586 As assumed, if the considered condition is that the level of Trip signal should be equal to 1 for state2, the result of assessment will be passed. 50 00:02:52,619 --> 00:02:54,760 Specifying the binary levels 51 00:02:54,790 --> 00:03:01,687 In the “level assessment” tab, the number of binaries defined in “hardware configuration”, column is added with the same name. 52 00:03:01,711 --> 00:03:08,367 In this part, you can set the level one or zero regardless of the binary level condition i.e. X. 53 00:03:08,391 --> 00:03:13,820 In this film, the goal is the assessment of the level one of the binary 3 (Trip) in “state2”. 54 00:03:13,844 --> 00:03:22,149 Suppose that the level of binary 3 before and after the second “state” is equal to one for “40” ms and assessment result is pass. 55 00:03:22,201 --> 00:03:31,481 For this purpose, the value of “40” ms is inserted in “state2” in the field “tolerance”, and the level one is inserted in the field “Trip” (binary 3). 56 00:03:31,505 --> 00:03:37,392 A comment about the assessment can be inserted in “user comment” that is also used in the output report. 57 00:03:37,417 --> 00:03:39,543 Then run the test 58 00:03:43,488 --> 00:03:48,150 After the test, assessment is done and the result is presented in “assessment”. 59 00:03:48,174 --> 00:03:51,533 As seen in “signal view”, before and after the “state2”, 60 00:03:51,557 --> 00:03:58,444 binary one has been preserved for at least “40” ms. So, the result of assessment is “pass”.